The solution to the equation x(x+4) = 6 is x = -2 + √10 or x = -2 - √10 after solving with the quadratic formula.
<h3>What is a quadratic equation?</h3>
Any equation of the form where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:
We have an equation:
x(x + 4) = 6
By distributive property:
x² + 4x = 6
x² + 4x - 6 = 0
a = 1, b = 4, c = -6
Plugging all the values in the formula:
After calculating:
Thus, the solution to the equation x(x+4) = 6 is x = -2 + √10 or x = -2 - √10 after solving with the quadratic formula.
Learn more about quadratic equations here:
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Answer:
Chlorine, Krypton, Argon, Fluorine, Hydrogen
Step-by-step explanation:
Look at the numbers and sort them from least to greatest. It could be the opposite answer to since the larger the negative number the smaller the value.
5 hours 380 cookies
--------- = -----------------
5 5
380/5 = 76 cookies made each hour
Answer:
The answer is C. y=2x+3
Step-by-step explanation:
A. y=3x you would pick a coordinate to replace the X and Y value. -1=3(-2) which gives you -1=-6, which wouldn't work.
B. y=x+1 you would pick a coordinate to replace the X and Y value. -1=-2+1 which would give you -1=-1 which would work, but you have to check all of the coordinates to make sure it is the correct one. 3=0+1 which would give you 3=1 so this is not the correct answer.
C. y=2x+3 You would pick a coordinate to replace the X and Y value. -1=2(-2)+3 so then you would simplify that which would give you -1=-1 which would work, but you still need to check to make sure that all of the coordinates work. 3=2(0)+3 which would give you 3=3. 9=2(3)+3 which would give you 9=9. Since this one is able to have three coordinates that can be plugged into it more than likely it is the correct answer, but just to be certain lets see if D will work.
D. y=x+13 you would substitute the coordinates for the x and y values -1=-2+13 which would give you -1=11 which would not be correct.