its 1, if its not, your school's thing sucks and needs to be reprogramed
Answer:
0.9375
Step-by-step explanation:
Given the following :
Number of coin tosses = 7
Probability that number of heads obtained will be between 2 and 7 inclusive?
x = 2,3,4,5,6,7
Probability (P) = number of required outcomes / total possible outcomes
For a coin toss = 1 Head (H), 1 tail (T)
P(H) = 1 / 2
P(X) = C(7,x) * (1/2)^7
P(X) = C(7, x) / 0.5^-7
P(X) = [C(7,2) + C(7, 3)+ C(7,4) +C(7,5) + C(7,6) +C(7,7)] / 128
P(X) = (21 + 35 + 35 + 21 + 7 + 1) / 128
P(X) = 120 / 128
P(X) = 0.9375
Answer: 102
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We'll use the formula
A = h*(b1+b2)/2
where
A = area of trapezoid
h = height
b1 & b2 are the parallel bases
In this case,
b1 = 6+7 = 13
b2 = 21
h = 6
Making the area to be
A = h*(b1+b2)/2
A = 6*(13+21)/2
A = 6*(34)/2
A = 204/2
A = 102
Side Note: We don't use the slanted side of 10 cm at all
To evaluate the expression all you have to do is substitute the value for the variable.
3 + y + 6, y = 5
3 + 5 + 6
8 + 6
14.
The solution is 14.
5 and 96/100 or if you need to simplify 5 and 24/25
