The English alphabet contains 26 letters (a, b, c, ...y, z).
The digits from 0 to 9 are a total of 10.
A keycode contains 2 letters, and 3 numbers, for example:
AB 598; MM 139; NT 498; ...
So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of
26*26=676 possible pairs of letters.
Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :
10*10*10=1,000 possible triples of numbers.
Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of
676*1,000=676,000 keycodes.
Answer: 676,000
Answer:
1/6
Step-by-step explanation:
Answer:
Step-by-step explanation:
How to factor expressions?
Find the G.C.F. and divide it into the terms of the expression you need to factor, like this:
. So I took the 12 and pulled it out of both terms, obtaining 
.
Answer:
D
Step-by-step explanation:
x^2+2x-5-(-3x^2-4x+1)
x^2+2x-5+3x^2+4x-1
4x^2+6x-6
Answer:
$793.00
Step-by-step explanation:
109x7=763
763+30=793
