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2 years ago

A statement that is true from a rhombus

Mathematics

1 answer:

Talja [164]2 years ago

8 0

A rhombus has two sets of parallel sides. A rhombus has two pairs of angles

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2025bellikar avatar

Novosadov [1.4K]

Answer:

sweet

Step-by-step explanation:

This took 80 minutes

3 0

2 years ago

(1,3), m = - 3/4 using that as a fraction write an equation in point-slope form

sukhopar [10]

Y=mx+b m=-3/4 (1,3)
3=-3/4(1)+b
3=-3/4+b
b=3 3/4

y=-3/4+3 3 3/4

7 0

2 years ago

{(-9,3) (5,-6) (3,-1), (-6,5), ?}Which ordered pair can replace the missing value and make the set if ordered pairs NOT a functi

Nookie1986 [14]

$\text{Slope}=\frac{-1--6}{3-5}=\frac{5}{-2}$ $\begin{gathered} y-y_1=\frac{5}{-2}(x-x_1) \\ \\ y--6=\frac{5}{-2}(x-5) \\ \\ -2(y+6)=5(x-5) \\ -2y-12=5x-25 \\ 5x+2y=25-12 \\ 5x+2y=13 \end{gathered}$

The missing values are (-6, -9) ( The last option)

Explanation:

x= - 6 has already produced the value of y as 5, the only pair in the given option the make the given ordered pairs NOT to be a function is (-6, -9) since it will give the value of y to be - 9.

4 0

7 months ago

Which expressions are equivalent to Negative 9 (two-thirds x + 1)? Check all that apply.

Sav [38]

Answer:

$-9(\frac{2}{3}x) + 9(1)\\ \\-6x + 9$

Explanation:

Before we begin, remember the following rules:

1- Distribution property:

$a(b+c) = ab+ac$

2- Simplification of fractions:

$\frac{xy}{yz}=\frac{x}{z}$

3- Signs in multiplication:

+ve * +ve = +ve

-ve * -ve = +ve

+ve * -ve = -ve

Now, for the given problem, we have:

$9 (\frac{2}{3}x + 1)$

Starting with the distributive property:

$-9 (\frac{2}{3}x +1) = -9(\frac{2}{3}x) - (-9)(1) = -9(\frac{2}{3}x) + 9(1)$

..................>This corresponds to option 1

Now, we simplify the output from the above step:

$-9(\frac{2}{3}x) + 9 = \frac{-9*2}{3}x + 9 = -6x+9$

................> This corresponds to option 5

Hope this helps :)

4 0

2 years ago

Read 2 more answers

1. Trapezoid BEAR has a height of 8.5 centimeters and parallel bases that measure 6.5 centimeters and 11.5 centimeters. To the n

e-lub [12.9K]

<h3>Given</h3>

1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.

2) Regular pentagon PENTA with side lengths 9 m

The area of each figure, rounded to the nearest integer

<h3>Solution</h3>

1) The area of a trapezoid is given by

... A = (1/2)(b1 +b2)h

... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77

The area of BEAR is about 77 cm².

2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...

... A = (1/2)ap

... A = (1/2)(s/(2tan(180°/n)))(ns)

... A = (n/4)s²/tan(180°/n)

We have a polygon with s=9 and n=5, so its area is

... A = (5/4)·9²/tan(36°) ≈ 139.36

The area of PENTA is about 139 m².

6 0

2 years ago