a+b+c=0
[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]
[a^2+b^2+c^2+2ab+2ac+2bc=0]
[a^2+b^2+c^2=-(2ab+2ac+2bc)]
[a^2+b^2+c^2=-2(ab+ac+bc)] (i)
also
[a=-b-c]
[a^2=-ab-ac] (ii)
[-c=a+b]
[-bc=ab+b^2] (iii)
adding (ii) and (iii) ,we have
[a^2-bc=b^2-ac] (iv)
devide (i) by (iv)
[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
Answer:
<em><u>[</u></em><em><u>2</u></em><em><u>,</u></em><em><u>4</u></em><em><u>,</u></em><em><u>6</u></em><em><u>]</u></em>
Step-by-step explanation:
GIVEN EQUATION : 2X+3≥7
i.e, 2x≥7-3
i.e, 2x≥4
i.e, x≥4/2
i.e, x≥2
it's represent number should be greater than or equal to 2
The only number which follows the inequality from the set is 2,4&6
✌️:)
Answer:
They are supplementary
Step-by-step explanation:
Two Angles are Supplementary when they add up to 180 degrees.
