The number of zeros in both the quotient are the same (both have 3 0's).
1.
2x-2=2x+32x-2=2x+3
notice
2x-3=2x+2
minus 2x both sides
-3=2
false
no solution
2. 5m-4=7m+85m-4
add 4 to both sides
5m=92m
therefor m=0
but wait
5m-4=7m+8
5(0)-4=7(0)+8
-4=8
false
no solution
3.
y+7=y-3
minus y both sides
7=-3
false
no solution
none of them have solutions
Answer:
(1)5 - 0.5(5) = 5 - 2.5 =======2.5
Step-by-step explanation:
Answer:
Part 1
The mistake is Step 2: P + 2·x = 2·y
Part 2
The correct answer is
Step 2 correction: P - 2·x = 2·y
(P - 2·x)/2 = y
Step-by-step explanation:
Part 1
The student's steps are;
Step 1; P = 2·x + 2·y
Step 2: P + 2·x = 2·y
Step 3: P + 2·x/2 = y
The mistake in the work is in Step 2
The mistake is moving 2·x to the left hand side of the equation by adding 2·x to <em>P </em>to get; P + 2·x = 2·y
Part 2
To correct method to move 2·x to the left hand side of the equation, leaving only 2·y on the right hand side is to subtract 2·x from both sides of the equation as follows;
Step 2 correction: P - 2·x = 2·x + 2·y - 2·x = 2·x - 2·x + 2·y = 2·y
∴ P - 2·x = 2·y
(P - 2·x)/2 = y
y = (P - 2·x)/2
12 out of 20
Your answer is the question
