Answer:
heptan-3-one and heptan-2-one
Explanation:
In this case, we must remember what the products of this reaction are. An alkyne in the presence of HgSO4 and H2SO4 will produce a ketone. But, in the triple bond, we have two carbons, therefore the carbonyl group can be placed on any of the carbons of the triple bond.
In figure 1 we have the general reaction. At C = O it can be added to the carbon on the left (red carbon) or the carbon on the right (blue carbon).
Following this logic, for 2-heptyne the carbonyl group can be added to carbon 2 producing <u>heptan-2-one</u>. Similarly, the carbonyl group can be added to carbon 3 producing <u>heptan-3-one</u>. (See figure 2)
Phosphorus is the element among the elements given in the question that if <span>combined with chlorine, will have the greatest attraction for the chlorine electrons. The correct option among all the options given in the question is the second option or option "b" and the fact is that you have chosen correctly. </span>
Answer:
by using this formula you will get it
Explanation:
number of mole = number of particles÷ Avogadro's number
n=3.51×10^23÷ 6.02×10^23
n = 0.58 moles
Answer: 0.1 meters
Explanation: move ten down a place value and u get .10 which is equal to 0.1 meters