<h2>Answer</h2>
<h2>Explanation </h2>
First we are going to find the equation of the solid line passing trough the points (0, 3) and (2, 4).
Using the slope formula:
Now we can use the point slope formula to complete the line equation:
Since the shaded region is bellow the line , the inequality represented in the graph is .
Let 3<em>n</em> + 1 denote the "number" in question. The claim is that
(3<em>n</em> + 1)² = 3<em>m</em> + 1
for some integer <em>m</em>.
Now,
(3<em>n</em> + 1)² = (3<em>n</em>)² + 2 (3<em>n</em>) + 1²
… = 9<em>n</em>² + 6<em>n</em> + 1
… = 3<em>n</em> (3<em>n</em> + 2) + 1
… = 3<em>m</em> + 1
where we take <em>m</em> = <em>n</em> (3<em>n</em> + 2).
Answer
3
Step-by-step explanation:
h(-6)=-(-6)-3
h(-6)=6-3
h(-6)=3
Answer: -1
Step-by-step explanation: First, factor out 3.6. You should get -m+3. Since the coefficient is just the number being multiplied to the variable (which is m here), your coefficient should be -1 because m is being multiplied to -1 to make -m. Hope this helps!
I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have
C(8,3) = 8!/(8-3)!3!
C(8,3) = 56
There are 56 3-person teams that can be formed from the 8 students.
