Answer:
Different liquid
Explanation:
<em>The independent variable in the investigation is the different liquid given to the plants.</em>
<u>The independent variable in an experimental investigation is the variable that is supplied by the researcher which directly affects the main variable being measured during the investigation. In other words, the independent variable is a variable that directly affects the dependent variable.</u>
In this case, the dependent variable would be growth determining factors in plants such as height, biomass, number of leaves, etc. while the independent variable would be the different types of liquid given to the plants.
Answer:
P= 138.6 atm or 1.4x10²
Explanation:
You will need to use PV=nRT to solve for P, pressure
Where the R constant is 0.08206 L atm mol^-1 K^-1
V is 1.2 L
T is temperature in kelvin, 273.15+25= 298.15
n is 6.8 mol
P*1.2=6.8*0.08206*298.15 ---> P*1.2=166.3700852 ---> P=166.3700852/1.2
P=138.6 atm
or 1.4x10²
Answer:
I am pretty sure that it is C
Explanation:
Answer:
Explanation:
We must use the Nernst equation
Step 1. Calculate E°
Anode: Cd ⟶ Cd²⁺(x mol·L⁻¹) + 2e⁻; E° = +0.4030 V
<u>Cathode: Ni²⁺ (1.00 mol·L⁻¹) + 2e⁻ ⟶ Ni; E° = - 0.257 V
</u>
Overall: Ni²⁺(1.00 mol·L⁻¹) + Cd ⟶ Ni + Cd²⁺ (x mol·L⁻¹); E° = 0.146 V
Step 2. Calculate Q
3. Calculate [Cd²⁺]
![\begin{array}{rcl}Q & = & \dfrac{\text{[Cd$^{2+}$]}}{\text{[Ni}^{2+}]}\\\\1.14 \times 10^{-3} & = & \dfrac{x}{1.00}\\\\x& = & 1.14 \times 10^{-3}\\\end{array}\\\text{The concentration of Cd$^{2+}$ is $\large \boxed{\textbf{1.14 $\times \mathbf{10^{-3}}$ mol/L}}$}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7DQ%20%26%20%3D%20%26%20%5Cdfrac%7B%5Ctext%7B%5BCd%24%5E%7B2%2B%7D%24%5D%7D%7D%7B%5Ctext%7B%5BNi%7D%5E%7B2%2B%7D%5D%7D%5C%5C%5C%5C1.14%20%5Ctimes%2010%5E%7B-3%7D%20%26%20%3D%20%26%20%5Cdfrac%7Bx%7D%7B1.00%7D%5C%5C%5C%5Cx%26%20%3D%20%26%201.14%20%5Ctimes%2010%5E%7B-3%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20concentration%20of%20Cd%24%5E%7B2%2B%7D%24%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B1.14%20%24%5Ctimes%20%5Cmathbf%7B10%5E%7B-3%7D%7D%24%20mol%2FL%7D%7D%24%7D)
