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2 years ago

5

ASAP The ratio of the width to the length of a ratio is1:3 which of the following ratio represents a rectangle with an equivalen

t ratio?

1 answer:

Soloha48 [4]2 years ago

4 0

Take whatever side lengths you have and divide that number by 1/3 in your calculator and what number is shown after doing this is the answer

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Can you guys solve this

forsale [732]

Answer:

A is -4 B is 2.5 C is 4 D is -2.5

Step-by-step explanation:

3 0

1 year ago

Read 2 more answers

Line AB contains points A (4,5) and B(9,7). What is the slope of AB

ki77a [65]

This line crosses the point (4,5)so we can make an equation to find the slope:
$4 = a \times 5 \\ 4 = 5a \\ a = \frac{4}{5}$
hope this helps

8 0

2 years ago

Read 2 more answers

Tell whether each function is linear or non-linear.

MrMuchimi

Answer:

Function A is non-linear and Function B is linear.

Step-by-step explanation:

Linear function:

Has the following format:

y = mx + b

In which m is the slope and b is the y-intercept.

In a linear function, when x changes by 1, y will always changes by the same amount.

Function A:

When x changes by 1, y can change by various amounts. So function A is non-linear.

Function B:

y = -x + 5

In the format of a linear function, so linear

3 0

2 years ago

Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200

-Dominant- [34]

Answer:

1348 light years.

Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.

$(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)$

Upon substituting our given values in above formula we will get,

$x^2=1200^2+1700^2-2*1200*1700*cos (52^o)$

$x^2=1440000+2890000-4080000*0.615661475$

$x^2=4330000-2511898.81933008$

$x^2=1818101.18066992$

Let us take square root of both sides of our equation.

$x=\sqrt{1818101.18066992}$

$x=1348.3698234\approx 1348$

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

6 0

2 years ago

Help please!!!!!!!!!

finlep [7]

Kill me please I'm ugly

4 0

2 years ago