A−15=4a−3a solve for a

Mathematics

1 answer:

Vlada [557]2 years ago

6 0

Answer: A= -4

Step-by-step explanation:

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Anna [14]

Answer:

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Step-by-step explanation:

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5 0

2 years ago

Read 2 more answers

If 3, x, y, -9 are in A.P, find the values of x and y.

Serggg [28]

Answer:

x = -1
y = -5

Step-by-step explanation:

The common difference (d) can be found using the first and 4th terms:

a1 = 3

a4 = a1 +d(4 -1)

-9 = 3 +3d . . . . . simplify

-3 = 1 + d . . . . . . divide by 3

-4 = d . . . . . . . . . subtract 1

Then ...

x = a1 + d = 3 -4 = -1

y = x + d = -1 -4 = -5

The values of x and y are -1 and -5, respectively.

6 0

2 years ago

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$