Answer:
no solution
Step-by-step explanation:
ya gotta use your eyes and brain huney. it aint that hard. kk? but ill still explain for you.
since x+y=6 and x+y=4. then 4=6. but that is false so no solution.
YOUR WELCOME!
I did the math I think it’s 12
|r| ≤ 1
selection C cannot be a value of r.
<em>Yea online school does suck, but when u need help, they wont give u the help u need. And also u get called on to do something when u dont want to. Have a nice day!! :)</em>
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
