Answer:
Point of intersections are (0, -7) and (5, -2).
Step-by-step explanation:
From the graph attached,
A straight line is intersecting the circle at the two points (0, 7) and (5, -2).
Now solve algebraically,
Equation of the line → y = x - 7 -------(1)
Equation of the circle → (x - 5)² + (y + 7)² = 25 -------(2)
By substituting the value of y from equation (1) to equation (2)
(x - 5)² + (x - 7 + 7)² = 25
(x - 5)² + x² = 25
x² - 10x + 25 + x² = 25
2x² - 10x = 0
x² - 5x = 0
x(x - 5) = 0
x = 0, 5
From equation (1),
y = 0 - 7 = -7
y = 5 - 7 = -2
Therefore, point of intersections are (0, -7) and (5, -2).
<h3>
♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>
➷ r = k/v^2
Substitute the values in:
120 = k/1^2
Multiply both sides by 1^2 to find k
k = 120
Substitute new values in:
r = 120/10^2
Solve:
r = 1.2
<h3><u>
✽</u></h3>
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
Answer:
-5/2(3x+4)<6-3x (multiply with -5/2)
-15/2x-10<6-3x (multiply with 2)
-15x-20<12-6x (change sides)
-15x+6x<12+20
-9x<12+20
-9x<32
x>-32/9
Hope this will help u :)
Answer:
-5^11
Step-by-step explanation:
Answer:
1200000
Step-by-step explanation:
