Explanation:
The given data is as follows.
= 57 kg, = 79 kg
= 6.5 m, = (6.5 - 1.9) m = 4.6 m
(a) The sum of torque ends about far end is as follows.
= 0
= 0
T = 828 N
Therefore, 828 N is the tension in the cable closer to the painter.
(b) Now, we will calculate the sum about close ends as follows.
= 0
T= 506 N
Therefore, 506 N is the tension in the cable further from the painter.
Between centre of curvature and principal focus.
Answer:
-3m+7m = 4m
Explanation:
As he walks south, he is going down 3m (-3m). Then he walks up 7m (+7m).
You subtract the final position from the initial position to get displacement.
7m - 3m = 4m
Answer:
34.64 cm
Explanation:
Given that:
The depth of the hole h = 10 cm
height of the water holding in the tank H = 40 cm
For a stream of flowing water, the distance (x) at which the stream strikes the floor can be computed by using the formula;
x = 34.64 cm