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2 years ago

a person weighs 158.53 lb on earth and weighs 26.95 lb on the moon, how much does a 243.53 lb person weigh on the moon?

Mathematics

1 answer:

nataly862011 [7]2 years ago

3 0

Answer:

40.71

Step-by-step explanation:

find moon weight divided by earth weight gives weight multiplier coefficent, add some lamb sauce and pepper. bake in the oven at 500degrees for 10 miniutes, then wahla. moon gravity answer

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Can slope intercept form have y as the slope?<br><br> For example:<br> x = 7y

Mandarinka [93]

Answer:

yes

Step-by-step explanation:

The equation of the line is written in the slope-intercept form, which is: y = mx + b, where m represents the slope and b represents the y-intercept.

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1 year ago

I cant figure it out, and if I get this wrong I fail the test

Oliga [24]

Step-by-step explanation:

x = 1.21212121.....

100x = 121.21212121...

Therefore 99x = 120 and x = 120/99 = 40/33.

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2 years ago

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A rectangular prism is sliced by a horizontal plane. What is the shape of the cross-section?

Leni [432]

The shape would be a rectangle

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2 years ago

Help! I need to know the circumference of the circle and the area of the half circle! Use 3.14 for pi

dedylja [7]

Answer:

18.8495559215

Step-by-step explanation:

circumference = diameter * pi

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2 years ago

Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.

$1-0.99^n\geq 0.95\\0.99^n\leq 1-0.95\\0.99^n\leq 0.05\\n\geq 297$

4 0

2 years ago