Cotx = cosx/sinx
cscx = 1/sinx
If we plug these into your equation we get:
(cosx/sinx)/(1/sinx) - 1
Dividing by a number is the same as multiplying by its reciprocal so it can be rewritten as:
(cosx/sinx)(sinx) - 1
The two sinx's cancel each other out so we end up with cosx - 1
Answer:
Step-by-step explanation:
Step-by-step explanation:
when means of more than two groups are to be compared, ANOVA is perferred
Answer:
Step-by-step explanation:
a1 = 6
a2 = 10
a3 = 14
The next member of the sequence is 4 more than the current sequence. Therefore d = 4
a1 = 6
d = 4
n = 13
an = a1 + (n - 1)*d
an = 6 + (n - 1)*4
a_13 = 6 + 12*4
a_13 = 6 + 48
a_13 = 54
Answer:
hope it helps you .......