The equation of the tangent line at x=1 can be written in point-slope form as
... L(x) = f'(1)(x -1) +f(1)
The derivative is ...
... f'(x) = 4x^3 +4x
so the slope of the tangent line is f'(1) = 4+4 = 8.
The value of the function at x=1 is
... f(1) = 1^4 +2·1^2 = 3
So, your linearization is ...
... L(x) = 8(x -1) +3
or
... L(x) = 8x -5
The correct answer is 11944444
I think....
Answer:
Step-by-step explanation:
The opposite angles of a parallelogram are equal. Therefore, for parallelogram KLMN, <K = <M
X=3
Divide both sides of the equation by 2
X^3 =27
Write the number in exponential form with an exponent of 3
X^3=3^3
Since the exponents are the same, set the bases equal
X=3