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2 years ago

11

a batter hits a homerun in which the ball travels 110m horizontally with no appreciable air resistance. If the ball left the bat

at 50 degrees above the horizontal just above ground level,how fast was it hit?

1 answer:

e-lub [12.9K]2 years ago

7 0

If you know the formula for horizontal range, then finding the solution is immediate:

$r=\dfrac{{v_0}^2\sin2\theta}g$

$110\,\mathrm m=\dfrac{{v_0}^2\sin100^\circ}{9.8\,\frac{\mathrm m}{\mathrm s^2}}\implies v_0\approx33\,\dfrac{\mathrm m}{\mathrm s}$

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