We prove this by contradiction: Suppose there was an N for which we can construct a triangle with side lengths N, 2N, and 3N. We then apply the triangle inequalities tests. It must hold that:

N + 2N > 3N

3N > 3N

3 > 3

which is False, for any value of N. This means that the original choice of N is not possible. Since the inequality is False for any value of N, there cannot be any triangle with the given side lengths, thus proving our conjecture.

6 0

2 years ago

What are the 3 factors of 4,6,9,14,? and 49

OlgaM077 [116]

3 factors of 4, 6, 9, 14 and 49 are 2, 3 and 7

8 0

3 years ago

What are the solutions to the system of equations below 3y=x-2 y=-2x+4

Oduvanchick [21]

The value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have a system of the equation:

3y=x-2 ..(1)

y=-2x+4 ...(2)

From the equation (2) take the value of y and plug in the equation (1)

3(-2x+4) = x -2

-6x + 12 = x - 2

7x = 14

x = 14/7

x = 2

Plug this value in the equation (2)

y = -2(2) + 4

y = 0

Thus, the value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.

Learn more about the linear equation here:

brainly.com/question/11897796

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7 0

1 year ago