Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.
<h3>What is volume?</h3>
Volume is the area occupied by the substance and is the ratio of the mass to the density.
At STP, 1 mole of gas occupies 22.4 L of volume
Given,
Volume of ammonia reacted = 0.720 L
The combustion reaction is shown as,
From the stoichiometry of the reaction, it can be said that,
L of ammonia reacts with L of oxygen gas.
So, 0.720 L of ammonia will react with:
Therefore, the volume of oxygen required is 900 mL.
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Answer:
It is mentioned that the student is mixing chemicals A and B and observes the time taken for the color to change. However, in the experiment, it is noticed that the student has repeated the procedure five times and each time he or she is modifying the concentration of chemical B. Thus, it is clear that the concentration of chemical B is the independent variable in the experiment. An independent variable is illustrated as the variable, which is controlled or modified in the experiment.
Answer:
Explanation:
The mass of an atom is dependent on its number of protons and neutrons. Electrons have mass, but are too light in comparison to protons and neutrons to contribute towards the overall mass. Their relative mass is about 1/1840 compared to 1 for protons and neutrons, and therefore are not counted in the mass.
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Porque la temperatura de la agua es neutral
From all the calculations that were carried out, the concentration of 2atm is 0.0026 M.
<h3>What is molarity?</h3>
The term molarity is defined as the number of moles divided by the volume of the solution. Using the formula; C = kp where
- C = concentration
- k = constant
- p = pressure
C = 0. 0354 * 10^-3 g/28 g/mol × 1000/1 L
C = 0.0013 M
k = C/p = 0.0013 M/1 atm
k = 0.0013 Matm-1
Now;
C = 0.0013 Matm-1 * 2 atm
C= 0.0026 M
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