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2 years ago

Can 5.09 be an absolute value???

Mathematics

1 answer:

Anna11 [10]2 years ago

8 0

Of course. Any positive number can be an absolute value.

5.09 is the absolute value of +5.09 and also of -5.09 .

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Find the surface area of a cube<br> with side length 8.5 cm.

EastWind [94]

<h3>Answer: 433.5 square cm</h3>

=========================================================

Explanation:

A cube has 6 identical faces, all of which are squares.

Each square has a side length of 8.5 cm, so its area is (8.5)^2 = 72.25 sq cm.

The overall surface area, aka the area of all 6 faces combined, is 6*72.25 = 433.5 square cm

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2 years ago

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Find the slope of the line that passes through the points (10,-14) (-4,-2)

Annette [7]

Answer: 0.8571

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1 year ago

Find the average rate of change for the f(x) = 7(1.02)^x for x = 3 to x = 5.

shusha [124]

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2 years ago

10. Use the discriminant to find the values of b for which the equation 4x2 + bx + 1 = 0 has one real solution.

il63 [147K]

Answer:

b = 4, or -4

Step-by-step explanation:

b^2 - 4*4*1 = 0

b^2 = 16

b = 4, or -4

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1 year ago

PLEASE HELP ANSWER THESE QUESTIONS!

Sliva [168]

Answer:

Step-by-step explanation:

a² - b² = (a+ b)(a - b)

1) (2n-4/2n) ÷ (n^2-4/n)

$=\frac{2n-4}{2n}*\frac{n}{n^{2}-4}\\\\=\frac{2n-2*2}{2n}*\frac{n}{n^{2}-2^{2}}\\\\=\frac{2*(n-2)}{2n}*\frac{n}{(n+2)*(n-2)}\\\\=\frac{1}{n+2}$

2) [y^2-36/y^2-49] ÷[ y+6/y-7]

$=\frac{y^{2}-36}{y^{2}-49}*\frac{y-7}{y+6}\\\\=\frac{y^{2}-6^{2}}{y^{2}-7^{2}}*\frac{y-7}{y+6}\\\\=\frac{(y+6)*(y-6)}{(y+7)*(y-7)}*\frac{y-7}{y+6}\\\\=\frac{y-6}{y+7}\\$

3) [m^2-1/ m^2-m] ÷ [m^2-7m-8/3m ]

$=\frac{m^{2}-1}{m^{2}-m}*\frac{3m}{m^{2}-7m-8}\\\\=\frac{(m+1)*(m-1)}{m*(m-1)}*\frac{3m}{(m-8)*(m+1)}\\\\=\frac{3}{m-8}$

Hint : m² - 7m - 8

sum = -7

Product = -8

Factor = (-8), 1

m² - 7m - 8 =m² - 8m + m - 8

= m*(m - 8) + (m-8)

= (m - 8)(m +1)

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2 years ago