If the circumference is half of the perimeter than the area for both circles would be half of them find one circles area and half it
Let C and d be the circumference and diameter of a circle, respectively. Then
C = πd
so that
π = C/d = C/12
Any value you choose for x will make the equation a TRUE statement. This type of equation is called an identity, and the solution set is all real numbers.
Answer:
Minimum value of f(x) = -1.
Step-by-step explanation:
We convert it to vertex form:
x^2 - 6x + 8
= (x - 3)^2 - 9 + 8
= (x - 3)^2 - 1
The minimum value occurs when (x - 3)^2 = 0 because a square has a minimum value of zero ( it cannot be negative for real values of x).
So the function has a minimum value of -1.