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2 years ago

How can I find x if g(x)=16

Mathematics

1 answer:

Degger [83]2 years ago

5 0

Answer:

X is irrelevant, you cant! g(x) is the same as y so y=16.

Step-by-step explanation:

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Ms Rochelle wants to put her 29 students into 6 groups

slamgirl [31]

She needs 4 groups at the most, having 6 kids leftover, 6×4=24, not that hard

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2 years ago

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Find the inverse of the following function. Then prove they are inverses of one another.

solmaris [256]

Answer: $\dfrac{x^2+1}{2}$

Step-by-step explanation:

Given

$f(x)=\sqrt{2x-1}$

We can write it as

$\Rightarrow y=\sqrt{2x-1}$

Express x in terms of y

$\Rightarrow y^2=2x-1\\\\\Rightarrow x=\dfrac{y^2+1}{2}$

Replace y be x to get the inverse

$\Rightarrow f^{-1}(x)=\dfrac{x^2+1}{2}$

To prove, it is inverse of f(x). $f(f^{-1}(x))=x$

$\Rightarrow f(f^{-1}(x))=\sqrt{2\times \dfrac{x^2+1}{2}-1}\\\\\Rightarrow f(f^{-1}(x))=\sqrt{x^2+1-1}\\\\\Rightarrow f(f^{-1}(x))=x$

So, they are inverse of each other.

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2 years ago

If y2 = x3 + 2, which statement is true? The equation is a function at all values of x. The equation is not a function. The equa

tatyana61 [14]

Answer:

The equation is not a function.

Step-by-step explanation:

We are given that

$y^2=x^3+2$

$y=\pm\sqrt{x^3+2}$

Function: It is mapping between the values of two sets A and B.

Each element of A has unique value in set B.

By definition of function

In given function

y has no unique value for each value of x.

Substitute x=0

$y=\pm \sqrt{0+2}=\pm \sqrt 2$

Hence, it is not a function.

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3 years ago

What is the sum of 43 and z is equal to 72.98.

lisov135 [29]

Answer:

x + 43 = 72.98

x = 29.98

Step-by-step explanation:

3 0

2 years ago

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MatroZZZ [7]

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

Answer: 9.8 × 10 (4 squared)

3 0

2 years ago