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2 years ago

What is the perpendicular line in slope form of the equation (-5,8);y=1/5x-1

Mathematics

2 answers:

Likurg_2 [28]2 years ago

7 0

Answer:

y = -5x - 17

Step-by-step explanation:

Perpendicular lines has the negative reciprocal slope, so the slope is -5.

The y-intercept can be found by using point (-5,8) and plugging it into the equation: 8 = -5(-5) + b, b = -17. Unless you are not looking for a specific line. Then anything can be used as d.

denpristay [2]2 years ago

5 0

Answer: Find the negative reciprocal of the slope of the original line and use the slope-intercept form y=mx+b to find the line perpendicular to y=1/5x−1. y=−5x−17

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Answer:

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Also, we know the following identity about $sin\theta$ and $cos\theta$ :

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Vladimir79 [104]

Answer:

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Step-by-step explanation:

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