Who has the most power? athlete A (bench presses 100 kg over 0.6 m in 0.5 s) athlete B (bench presses 150 kg over 0.6 m in 1.0 s
1 answer:
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Answer:
Theta1 = 12° and theta2 = 168°
The solution procedure can be found in the attachment below.
Explanation:
The Range is the horizontal distance traveled by a projectile. This diatance is given mathematically by Vo cos(theta) t. Where t is the total time of flight of the projectile in air. It is the time taken for the projectile to go from starting point to finish point. This solution assumes the projectile finishes uts motion on the same horizontal level as the starting point and as a result the vertical displacement is zero (no change in height).
In the solution as can be found below, the expression to calculate the range for any launch angle theta was first derived and then the required angles calculated from the equation by substituting the values of the the given quantities.
Answer:
Explanation:
For this case we can use the second law of Newton given by:
The friction force on this case is defined as :
Where N represent the normal force, the kinetic friction coeffient and a the acceleration.
For this case we can assume that the only force is the friction force and we have:
Replacing the friction force we got:
We can cancel the mass and we have:
And now we can use the following kinematic formula in order to find the distance travelled:
Assuming the final velocity is 0 we can find the distance like this: