a negative times a negative = a positive
so (a * b) + c = 12
(-2 * -3) +6 = 12
6+6 = 12
We are required to compare the magnitude for two earthquake intensity:
the larger intensity is 7.9
the smaller intensity is 3.7
thus the ratio of the intensity will be:
(larger intensity)/(smaller intensity)
=7.9/3.7
=2.135
~2
Thus we conclude that:
The larger earthquake's intensity was 2 times as great as the smaller earthquake's intensity.
Step-by-step explanation:
Given:
h=7in
w=9in
l=6in
Required:
v=?
Formula:
<em>v</em><em>=</em><em>l</em><em>*</em><em>w</em><em>*</em><em>h</em>
Solution:
v=l*w*h
v=6in*9in*7in
v=54in^2*7in
v=378in^3
Hope this helps ;) ❤❤❤
Area of the figure = 30.28 m²
Solution:
The given image is splitted into two shapes.
One is rectangle and the other is semi-circle.
Length of the rectangle = 6 m
Width of the rectangle = 4 m
Area of the rectangle = length × width
= 6 m × 4 m
= 24 m²
Area of the rectangle = 24 m²
Diameter of the semi-circle = 4 m
Radius of the semi-circle = 4 m ÷ 2 = 2 m
Area of the semi-circle =
Area of the semi-circle = 6.28 m²
Area of the figure = Area of the rectangle + Area of the semi-circle
= 24 m² + 6.28 m²
= 30.28 m²
Area of the figure = 30.28 m²
y =-3x + x + 9
Find y when x = 2
Substitute the value of x= 2 into the equation
y = -3(2) + 2 + 9
y = - 6 + 2 + 9
y = -4 + 9
y = 5
The answer is 5