Corey spent 25% of his savings on a printer at Louie’s Electronics.

3. Find the geometric mean of 4 and 10. (1 point) A. 20 B. 7 C. SQ root of 14 D. 2x SQ root of 10

mart [117]

Answer:

$2\sqrt10$

6.3 to the nearest 10th

Step-by-step explanation:

Hope this helped :)

7 0

2 years ago

What is the answer to 14x - 3= 10x + 1

slava [35]

Answer:

14x - 3 = 10x + 1

4x = 4

x = 1

4 0

3 years ago

A car travels for 4(t+3) hours at a constant speed of 10(t+3) km/h. If the total distance travelled by the car is 810 km, find t

IceJOKER [234]

Step-by-step explanation:

$\because \: time \times speed = distance \\ \therefore \: 4(t + 3) \times 10(t + 3) = 810 \\ \therefore \: 4(t + 3)^{2} = 81 \\ \therefore \: \{2(t + 3) \}^{2} = {9}^{2} \\ \therefore \: \{2(t + 3) \} = {9} \\ \therefore \: t + 3 = \frac{9}{2} \\ \therefore \: t = \frac{9}{2} - 3 \\ \therefore \: t = \frac{9 - 6}{2} \\ \therefore \: t = \frac{3}{2} \\ \therefore \: t = 1.5 \: hrs \\$

$\because \: time \times speed = distance \\ \therefore \: 4(t + 3) \times 10(t + 3) = 810 \\ \therefore \: 4(t + 3)^{2} = 81 \\ \therefore \: \{2(t + 3) \}^{2} = {9}^{2} \\ \therefore \: \{2(t + 3) \} = {9} \\ \therefore \: t + 3 = \frac{9}{2} \\ \therefore \: t = \frac{9}{2} - 3 \\ \therefore \: t = \frac{9 - 6}{2} \\ \therefore \: t = \frac{3}{2} \\ \therefore \: t = 1.5 \: hrs \\ speed \: of \: car = 10(t + 3) \\ \hspace{60 pt} = 10(1.5 + 3) \\ \hspace{60 pt}= 10 \times 4.5 \\ \red{ \boxed{ \bold{ \therefore \: speed \: of \: car = 45 \:km/ h}}} \\$

3 0

2 years ago

What is the standard deviation of the data set? 1, 4, 2, 2, 8, 7, 3 Round your answer to the nearest tenth.

fomenos

The Answer is 2.7 For Sure

4 0

2 years ago

Read 2 more answers

Can someone please help me with this :((

slavikrds [6]

Answer:Here ya go

Step-by-step explanation: your using diameter so you would have to first find the value of N after that find the answer for the parentheses and then find the answer for the diameter and get your answer by adding them together

6 0

2 years ago