Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Answer: 12
Step-by-step explanation:
Answer:
there are 0 solutions to the equation
Step-by-step explanation:
To know how many solutions are in the problem, we have to solve for x and see what result we have left. According to the result, we will know how many solutions there are
8x + 47 = 8(x + 5)
8x + 47 = 8*x + 8*5
8x + 47 = 8x + 40
8x - 8x = 40 - 47
0 = -7
As we can see we are left with an equality that is not fulfilled, this means that there is no solution to the problem, at least in the field of real numbers
Answer:
Step-by-step explanation:
it doesn't.
20.63 = 20 63/100 <===
20 5/8 = 20.625