Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p
a. 1/2
b. 2 times
c. 1/4
d. 4 times
Answer:
4 times
Step-by-step explanation:
Given the following :
Distance between q and S (r) = 1 unit
Distance between P and S (r) = 2 × 1 unit = 2
According to coliumbs law:
F = Ke(q1q2) /r^2
Where F = electrostatic force, Ke = coloumbs constant
q1,q2 = charges, r = distance between two charges
For q and S :
Fsq = Ke(q1q2) / 1^2
Fsq = Ke(q1q2) - - - - - equation 1
For P and S :
Fsp = Ke(q1q2) / 2^2
Fsp = Ke(q1q2) / 4 - - - - - equation 2
Dibiding equation 1 by equation 2
Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4
Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)
Fsq / Fsp = 4 / 1
Using cross multiplication
Therefore, Fsq = 4 × Fsp
Answer:
4x -3
Step-by-step explanation:
The distributive property applies.
3x +4(x -6) -3(x -7)
= 3x +4x +4(-6) -3x -3(-7) . . . . use the distributive property
= 3x +4x -24 -3x +21 . . . . . . . . simplify
= x(3 +4 -3) +(-24 +21) . . . . . . . group like terms, use the distributive property again
= 4x -3 . . . . simplify
Answer:
See attached picture.
Step-by-step explanation:
Graph the function as (x,y) points.
(-3,5)
(4,6)
(6,-9)
(9,-10)
These are graphed in black on the picture.
To graph the inverse, switch the points from (x,y) to (y,x).
(5,-3)
(6,4)
(-9,6)
(-10,9)
These are graphed in red on the picture.
Oh, this is easy. For any prism, you find the surface area by finding the are of all the sides. I will post all surface area formulas here, for reference
Cube:
Surface area = 6 × a2
Right circular cylinder:
Surface area = 2 × pi × r2 + 2 × pi × r × h
pi = 3.14
h is the height
r is the radius
Rectangular prism:
Surface area = 2 × l × w + 2 × l × h + 2 × w × h
l is the length
w is the width
h is the height
Sphere:
Surface area = 4 × pi × r2
pi = 3.14
r is the radius
Right circular cone:
Surface area = pi × r2 + pi × r ×( √(h2 + r2))
pi = 3.14
r is the radius
h is the height
l is the slant height
Right square pyramid:
Surface area = s2 + 2 × s × l
s is the length of the base
h is the height
l is the slant height