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2 years ago

the angle of depression from a plane to the airport is 34°. the pilot reports that the plane's altitude is 3200 feet . find the

horizontal distance between the plane and the airport to the nearest foot

Mathematics

1 answer:

Aleksandr-060686 [28]2 years ago

6 0

$look\ at\ the\ picture\\\\cot34^o=\frac{x}{3200}\\\\cot34^o\approx1.4826\\\\\frac{x}{3200}=1.4826\ \ \ \ /\cdot3200\\\\x=4744.32\ (ft.)\approx4744\ (ft.)\leftarrow answer$

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Sever21 [200]

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$\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}$

Since $\alpha$ lies in quadrant II, we have $\cos\alpha$ , so

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$\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}$

$\beta$ lies in quadrant I, so $\sin\beta>0$ and

$\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}$

So

$\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}$

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stira [4]

Answer:

x = 6

Step-by-step explanation:

Since the triangle is equilateral then sides are congruent.

Equate any 2 sides and solve for x

13x + 5 = 8x + 35 ( subtract 8x from both sides )

5x + 5 = 35 ( subtract 5 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

JK = (13 × 6) + 5 = 78 + 5 = 83

KL = (17 × 6) - 19 = 102 - 19 = 83

JL = (8 × 6) + 35 = 48 + 35 = 83

ΔJKL is equilateral with side = 83

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Answer:

Step-by-step explanation:

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