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2 years ago

NEED HELP ASAP PLEASE

Mathematics

2 answers:

Irina18 [472]2 years ago

5 0

Answer:

y=5/2x-14

Step-by-step explanation:

Lines parallel to each other have the same slope this means you can take out the third and fourth answers. With the given slope you can solve for the equation of the line that goes through (-6, -29). Do this by plugging in (-6, -29) as x and y values and plugging in 5/2 as the slope.

(-29)=5/2(-6)+b, Solve for b

-29=-15+b

-14=b, The equation of the line is y=5/2x-14

kaheart [24]2 years ago

4 0

Answer:

y = 2½x - 14

Step-by-step explanation:

Remember, "parallel" in Geometry and Algebra means that they have SIMILAR rate of changes [slopes]. This is how your work should look:

-29 = 5⁄2[-6] + b

+15 -15

+15

------------------

-14 = b

Here is your parallel equation:

y = 2½x - 14 [5⁄2 = 2½]

I am joyous to assist you anytime.

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Wewaii [24]

Answer:

5 11/12

Step-by-step explanation:

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18/24 and 124/24

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2 years ago

Which pair of angles are congruent? A) 1 and 8 B) 4 and 6 C) 5 and 6 D) 1 and 7

taurus [48]

Answer:

Step-by-step explanation:

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2 years ago

P(A)=.50 P(B)=.40, and P(A and B) = .15 what is P(a and B)

seropon [69]

Answer:

0.75

Step-by-step explanation:

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2 years ago

Read 2 more answers

PLEASE HELP ME I BEG IMMA FAILLLLLLLLLLLLLLLL

Irina18 [472]

Answer:

7:1

Step-by-step explanation:

There are two cubes, one with 14 cm and one with 2 cm. 14:2 is equal to 7:1.

4 0

2 years ago

A rectangular box has a square base. The combined length of a side of the square base, and the height is 20 in. Let x be the len

aniked [119]

Answer:

a. V = (20-x) $x^{2}$ $in^{3}$

b . 1185.185 $in^{3}$

Step-by-step explanation:

Given that:

The height: 20 - x (in )
Let x be the length of a side of the base of the box (x>0)

a. Write a polynomial function in factored form modeling the volume V of the box.

As we know that, this is a rectangular box has a square base so the Volume of it is:

V = h * $x^{2}$ $in^{3}$

<=> V = (20-x) $x^{2}$ $in^{3}$

b. What is the maximum possible volume of the box?

To maximum the volume of it, we need to use first derivative of the volume.

<=> dV / Dx = -3 $x^{2}$ + 40x

Let dV / Dx = 0, we have:

-3 $x^{2}$ + 40x = 0

<=> x = 40/3

=>the height h = 20/3

So the maximum possible volume of the box is:

V = 20/3 * 40/3 *40/3

= 1185.185 $in^{3}$

7 0

2 years ago