Answer: The concentration of is 0.234 M
Explanation:
According to the neutralization law,
where,
= basicity = 2
= molarity of solution = ?
= volume of solution = 50.0 ml
= acidity of = 1
= molarity of solution = 0.375 M
= volume of solution = 62.5 ml
Putting in the values we get:
Therefore concentration of is 0.234 M
Rubidium is an element that belongs to Group 1. As such it will have physical properties similar to the other Group 1 elements. Rubidium is below
Potassium in the periodic table but above
Cesium. As such it would be most like one of those two elements.
Another name for chemical change would be chemical reaction.
The theoretical yield of NaBr given that 2.36 moles of FeBr₃ reacts is 7.08 moles
<h3>Balanced equation </h3>
2FeBr₃ + 3Na₂S → Fе₂S₃ + 6NaBr
From the balanced equation above,
2 moles FeBr₃ reacted to produce 6 moles of NaBr
<h3>How to determine the theoretical yield of NaBr</h3>
From the balanced equation above,
2 moles FeBr₃ reacted to produce 6 moles of NaBr
Therefore,
2.36 moles FeBr₃ will react to produce = (2.36 × 6) / 2 = 7.08 moles of NaBr
Therefore,
Thus, the theoretical yield of NaBr is 7.08 moles
Learn more about stoichiometry:
brainly.com/question/14735801
#SPJ1
The given question is incomplete. The complete question is:
A sample of household ammonia has a pH of 11.50. What is the hydronium ion concentration of this solution?
Answer: The hydronium ion concentration of the solution is
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration. Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.
Thus hydronium ion concentration of this solution is