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2 years ago

When the height of the cylinder increased by a factor of 5from 100 m to 500 m, what happened to the cylinder's

Physics

1 answer:

Lesechka [4]2 years ago

6 0

Answer: It increased by a factor of 5

Explanation:

Gravitational potential energy $P$ is given by the following formula:

$P=mgh$

Where:

$m$ is the mass of the cylinder (assumed as constant)

$g$ is the acceleration due gravity (assumed as constant)

$h$ is the height of the cylinder

As we can see, $P$ is directly proportional to $h$ . Hence, if $h$ increases by a factor of 5 $P$ increases by a factor of 5, as well.

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xz_007 [3.2K]

Answer:

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Explanation:

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2 years ago

How many doctors are ther in Edmonton

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2 years ago

Along the line connecting the two charges, at what distance from the charge q1 is the total electric field from the two charges

Nostrana [21]

Answer:

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

Explanation:

Here two charges are placed at distance "d" apart

now the net value of electric field at some position between two charges will be ZERO

so we will have

electric field due to charge 1 = electric field due to charge 2

$E_1 = E_2$

Let the position where net field is zero will lie at distance "r" from q1

$\frac{kq_1}{r^2} = \frac{kq_2}{(d-r)^2}$

now we will have

$\frac{(d - r)^2}{r^2} = \frac{q_2}{q_1}$

now square root both sides

$\frac{d}{r} - 1 = \sqrt{\frac{q_2}{q_1}}$

now we have

$\frac{d}{r} = \sqrt{\frac{q_2}{q_1}} + 1$

so we have

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

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2 years ago

The phases of the moon depend on how much of the lighted side of the moon can be seen from earth.is this true or false

Sindrei [870]

The answer to this question is going to be False

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2 years ago

In a car with a mass of 4,000 KG is accelerating at a rate of 2m/s2 and hits a tree what force does it have

Ilia_Sergeevich [38]

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F=ma

=4000kg * 2m/s 2 =8000N

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2 years ago