The electrical force acting on a charge q immersed in an electric field is equal to
where
q is the charge
E is the strength of the electric field
In our problem, the charge is q=2 C, and the force experienced by it is
F=60 N
so we can re-arrange the previous formula to find the intensity of the electric field at the point where the charge is located:
Answer:
Velocity(v) = frequency(f) × wavelength
f = 0.3165
Wavelength = 2×length(L)
L = 157cm
Convert the length in centimetres to metre = 1.57m
v = 2×1.57 × 0.3165
v = 0.99m/s
Approx. 1m/s
Explanation:
The velocity of a wave is the product of its frequency and it's wavelength. The frequency is already known. The wavelength is the distance between two successive wave crests which is formed by sloshing water back and forth in the bath tub. Sloshing water to one end of the tub will produce a wave crest first at that end then the other completing a cycle. The wavelength will be twice the length of the bath tub as it is the distance that both crests are formed.
Wave crest is the highest point of a wave, and in this case is where the water rises to a high point in the bath tub
1) hypothesis
2) data
3) method
I think these are correct.