Hey there !
The answer would be C. 0.68L
Hope this helps !
1) Cellulose - extracellular location, glycosidic bond, β-linkage. Cellulose is polysaccharide composed of glucose linked with β-1,4 bons.
2) Messenger RNA - informational macromolecule, phosphodiester bridge, helical structure possible, synthesis requires a template. mRNA is nucleic acid, <span> mRNA is </span>translated<span> into a polymer of amino acids.</span><span>
3) </span>Globular protein - peptide bond, helical structure possible, synthesis requires a template. Protein is composed of amino acid linked with peptide bond, secundary structure can be α-helix, gene expression.<span>
4) </span>Amylopectin - branched-chain polymer, glycosidic bond, helical structure possible. Amylopectin is subunit of starch, sugar with α-1,4 and α-1,6 glycosidic bonds.<span>
5) DNA - i</span>nformational macromolecule, phosphodiester bridge, helical structure possible, synthesis requires a template, nucleoside triphosphate. DNA is helical <span>chain of </span>nucleotides<span> carrying the </span>genetic<span> instructions.</span>
6) Fibrous protein - peptide bond, helical structure possible. Protein is composed of amino acid linked with peptide bond
O2, H2O and CO2. N2 is just a molecule I believe. Hope this helps!! Have a wonderful day!
So,
Given the reaction:
The initial mass of Mg was 0.326, and, in the real experiment, we obtained 0.528 grams of MgO. Right?
Now, let's find the amount of MgO supposed to obtain according to the chemical equation:
Now, the amount that we were supposed to obtain, was 0.54g of MgO. (The result of mutiplying all the previous operations). This is the theoretical yield, what we obtained using the theory.
Now, as you discovered, the mass of MgO in the laboratory was 0.528g so that's the actual yield. This is, what you've found using the experimental process.
Finally, the percent yield can be found using the following equation:
And, we know both values, so let's just replace: