Answer:
I think the acceleration is 12m/s
Answer:
m 200 g , T 0.250 s,E 2.00 J
;
2 2 25.1 rad s
T 0.250
(a)
2 2
k m 0.200 kg 25.1 rad s 126 N m
(b)
2
2 2 2.00 0.178 mm 200 g , T 0.250 s,E 2.00 J
;
2 2 25.1 rad s
T 0.250
(a)
2 2
k m 0.200 kg 25.1 rad s 126 N m
(b)
2
2 2 2.00 0.178 m
Explanation:
That is a reason
Answer:
d = 100.8 ft
Explanation:
As we know that initial speed of the van is 40 miles then the stopping distance is given as 70 feet
here we know that
so here we have
now again if the speed is increased to 48 mph then let say the stopping distance is "d"
so we will have
now divide the above two equations
There is a repulsive force between two charged objects when they are of like charges/ they are likely charged (like charges repel each other)
Answer:
7.344 s
Explanation:
A = 0.15 x 0.3 m^2 = 0.045 m^2
N = 240
e = - 2.5 v
B1 = 0.1 T
B2 = 1.8 T
ΔB = B2 - B1 = 1.8 - 0.1 = 1.7 T
Δt = ?
e = - dФ/dt
e = - N x A x ΔB/Δt
- 2.5 = - 240 x 0.045 x 1.7 / Δt
2.5 = 18.36 / Δt
Δt = 7.344 s
