2 years ago

Expand each logarithm using the properties of logarithms.

1 answer:

6 0

A. = logb (3/7)^1/2
= logb 3^1/2 - logb 7^1/2
= 1/2(logb 3 - logb 7)

b. = log 7x^3 + log y^5
= log 7 + log x^3 + log y^5
= log 7 + 3 log x + 5 log y

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IgorC [24]

Answer:

We just need to evaluate and get f(2i)=0, f(-2i)=0.

Step-by-step explanation:

Since $i^2=-1$ , then $i^3=i^2i=-i$ , and we can apply this when we evaluate $f(x) =x^3 + 4x$ for 2i and -2i.

First we have:

$f(2i) =(2i)^3 + 4(2i)=2^3i^3+8i=8(-i)+8i=0$

Which shows that 2i is a zero of f(x).

Then we have:

$f(-2i) =(-2i)^3 + 4(-2i)=(-2)^3i^3-8i=-8(-i)-8i=8i-8i=0$

Which shows that -2i is a zero of f(x).

4 0

2 years ago

Harrizon [31]

Your answer is going to be Letter B

8 0

2 years ago

shepuryov [24]

Hope this helps

Answer = 4,328.12
4,000
300
20
8
0.1
0.02

4 0

2 years ago

bogdanovich [222]

they are the same so set them equal

3x-10=2x+40 now combine like terms

3x-2x=40+10

x=50

8 0

2 years ago

AleksAgata [21]

Yes very because if you use the wrong one your whole formula will turn out wrong

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2 years ago