8y - 11y + 6
Combine like terms
-3y + 6 is the simplified answer.
The last one is no solutions and the first on is <span>infinitely many solutions
and the second one is one solution. I am pretty sure! Hope this helps!</span>
Answer:
In five years, the enrollment would have been 10,724 students
Step-by-step explanation:
The general depreciation formula is given as;
P = I( 1 - r)^t
where P is the present population
I is the initial
r is the rate of depreciation = 4.5% = 4.5/100 = 0.045
t is 5 years
substituting these values;
P = 13,500 (1- 0.045)^5
P = 10,723.84
Correct answer is option BThe solution is listed below:
The equation given in the question has one unknown variable and so the value of k can definitely be found.
4/9(k + 4/7) = 3 1/3
4/9[(7k + 4)] = 10/3
4/(63k + 36) = 10/3
4 * 3 = 10 * (63k + 36)
12 = 630k + 360
12 - 360 = 630k
- 348 = 630k
Reversing both sides we get
630k = - 348
k = - 348/630
= - 174/315
= - 58/105
So the value of K comes out to be - 58/105 and it is not possible to simplify it further.