The Mean Value Theorem:
If a function is continuous on [ a, b ] and differentiable on ( a , b ) than there is a point c in ( a, b ) such that:
f ` ( c )= ( f ( b ) - f ( a ) ) / ( b - a )
f ` ( c ) = ( f ( 2 ) - f ( 0 ) ) / ( 2 - 0 )
f `( x ) = 10 x - 3
f ` ( c ) = 10 c - 3
2 f ` ( c ) = 16 - 2
f ` ( c ) = 7
7 = 10 c - 3
c = 1
Answer:
Yes, the function is continuous on [ 0, 2 ] and differentiable on ( 0, 2 ).
Answer:
x < 15
Step-by-step explanation:
Let's first expand the parentheses on both sides. Remember that when expanding parentheses, the result will be the sum of the products of the "outside number" with each of the "inside number".
On the left, the parenthetical expression is: -6(x + 4). Here, the outside term is -6 and the inside terms are x and 4. So:
-6(x + 4) = -6 * x + (-6) * 4 = -6x - 24
On the right, the parenthetical expression is: -5(x + 6). Here, the outside term is -5 and the inside terms are x and 6. So:
-5(x + 6) = -5 * x + (-5) * 6 = -5x - 30
Now put these back in:
-6(x + 4) + 9 > -5(x + 6)
-6x - 24 + 9 > -5x - 30
-6x - 15 > -5x - 30
x < 15
Thus the answer is x < 15.
Hope this helps!
Answer:
The mean amount spent = £14.80
The modal product is hoodies.
Step-by-step explanation:
Here
25 T shirts each costing £10 were purchased
Amount spent on T shirts = 25 × 10 = £250
30 key ring of £5 were purchased
Amount spent on key ring = 30 × 5 = £150
40 Hoodies for £25 each
Amount spent on Hoodies = 40 × 25 =£1000
30 CD's for £15 each
Amount spent on CD's = 30 ×15 = £450
Total amount spent = 250 +150 + 1000 + 450 = £1850
Total items purchased = 25 + 30 + 40 + 30 = 125
Mean amount spent =
The modal product is Hoodies as the maximum number of hoodies were purchased.
let h = horse, let c = cow, let p = pig
so,
hcp
hpc
cph
chp
phc
pch
so, that is 6 different ways she can arrange it.