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3 years ago

Please help asap 50 pts

Mathematics

2 answers:

ZanzabumX [31]3 years ago

5 0

The answer is !C! because the axis of symmetry is the imaginary line that passes through the middle of the parabola which is -0.5, the vertex is the maximum or the minimum point which in this case it is the maximum point. since it can't be -0.5, 0.5 because the point is a negative x and y. if you plug in -0.5 to C's equation, -2(-0.5)^2+2(-0.5)-1 you would get f(x)=-0.5 which is the point that y equals Hope this Helps :)!

adoni [48]3 years ago

3 0

The answer is d

hope this helped!!

p.s. if you found this helpful please mark it as brainliest! it would mean a lot to me, thanks!

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Find the sum of the measures

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Answer:

720

Step-by-step explanation:

360/6= 60 (outside angles)

180-60=120 (inside angles)

120x6=720 (sum of inside angles)

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2 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

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1 year ago

What is the term of a 7-term geometric series if the first term is -11 the last term is -45,056 and the common ratio is -4

shutvik [7]

I assume you mean to ask how to find the sum of the seven terms?

You have

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...
$a_7=ra_6=r^6a_1$

So the sum is

$a_1+ra_1+r^2a_1+\cdots+r^6a_1=a_1(1+r+r^2+\cdots+r^6)=a_1\times\dfrac{1-r^7}{1-r}$

You know that $a_1=-11$ and $r=-4$ , so the sum is equal to

$-4\times\dfrac{1-(-4)^7}{1-(-4)}=-13108$

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2 years ago

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Answer:

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