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2 years ago

Determine the value of z so that the area under the standard normal curve .0500

Mathematics

1 answer:

cluponka [151]2 years ago

7 0

Z for the 5th percentile is about -1.6449

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In the diagram below of a parallelogram STUV, SV=x+3, VU 2x-1, and TU=4x-3. What is the length of SV?

Katena32 [7]

Answer:

$SV=5\ units$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In a parallelogram opposites sides are parallel and congruent

In this problem

$SV=TU$ ---> by opposite sides

substitute the given values

$x+3=4x-3$

solve for x

$4x-x=3+3\\3x=6\\x=2$

Find the length of SV

$SV=x+3$

substitute the value of x

$SV=2+3=5\ units$

5 0

2 years ago

It is 70cm long and has a circumference of 40cm what is the radius

Aleksandr [31]

The legnth is irrelivant

we know that
Circumference=2 times pi time radius

c=40
40=2 times pi times radius
divide both sides by 2
20=pi times radius
divide both sides b pi
20/pi=radius

the radius is 20/pi cm or aproximately 6.366199048 cm

4 0

2 years ago

Which expression is equivalent to 14x – 21?

Vlad1618 [11]

The common factor is 7 so its

7(2x - 3)

8 0

2 years ago

PLEASE ANSWER ASAP!!!! (and actually answer the question, no begging for "brainliest")

Zepler [3.9K]

Answer:

A: P = 41100 - 590t

B: 34610

Step-by-step explanation:

equation = 41100-(41100-36380)/(2011-2003)t

plug it in

41100 - 590(2014-2003)=34610

4 0

1 year ago

p varies jointly as q and the square of r, and p = 200 when q = 2 and r = 3. Find p when q = 5 and r= 2.

Margarita [4]

Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

$\frac{p}{q {r}^{2} } = k$

where k is a constant

First, let find k. Substitute p= 200

q= 2, and r=3.

$\frac{200}{2(3) {}^{2} } = k$

$\frac{200}{18} = k$

$\frac{100}{9} = k$

Now, since we know our constant, let find p.

$\frac{p}{q {r}^{2} } = \frac{100}{9}$

Q is 5, and r is 2.

$\frac{p}{5( {2}^{2}) } = \frac{100}{9}$

$\frac{p}{20} = \frac{100}{9}$

$p = \frac{2000}{9}$

3 0

1 year ago