Kevin will water both of his plants on the 15th.
The lowest common multiple of 3 and 5 is 15. Therefore, he will water both then.
has critical points where the derivative is 0:
The second derivative is
and , which indicates a local minimum at with a value of .
At the endpoints of [-2, 2], we have and , so that has an absolute minimum of and an absolute maximum of on [-2, 2].
So we have
Answer:
Area = 2025 miles²
Perimeter = 180 miles
Step-by-step explanation:
Given the following :
Scale of drawing = 1 inch : 5 miles
Length of side of the scale drawing = 9 inches
To find The actual perimeter and area of the square, we need ;
Actual length of the drawing :
1 inch = 5 miles
9 inches = (5 × 9) miles = 45 miles
Hence,
Area of a square = a²
Where a = side length
Actual side length = 45 miles
Actual area of square = 45² = 2025 miles²
Actual Perimeter of square :
Perimeter of a square = 4a
a = side length
Actual perimeter = 4(45) = 180 miles
Step-by-step explanation: