The hundreds digit is twice as large as the ones digit. 3 doubled is 6, 6 doubled is 12, and 9 doubled is 18. Since 6 is the only option that is one digit, the hundreds digit must be 6 and the ones digit must be 3. The tens digit is five less than the hundreds digit.
Let us determine the product of 438 and 17 by partial products.
Consider
and
So,
=
= 7446
Therefore, the product of 438 and 17 is 7446.
No, Sandra's answer is not correct.
Because she should have expressed 17 as (10+7), then if she multiplied (438 by 10) and (438 by 7). And, then added the results.Then her answer would be correct.
Answer:66
Step-by-step explanation:
Answer:
<h2>0, 3, 8, 15</h2>
Step-by-step explanation:
Substitute n = 1, n = 2, n = 3 and n = 4 to the equation f(n) = n² - 1:
f(1) = 1² - 1 = 1 - 1 = 0
f(2) = 2² - 1 = 4 - 1 = 3
f(3) = 3² - 1 = 9 - 1 = 8
f(4) = 4² - 1 = 16 - 1 = 15
Answer:
A. P - Q
Step-by-step explanation:
Q(x) = (x³ + 2x² + 3)(x² -2)
= x⁵ - 2x³ + 2x⁴ - 4x² + 3x² - 6
P - Q = (x⁵ - 2x³ + 2x⁴ - 4x² + 3x² - 6) - (x⁴ + 3x³ + 2x² - x + 2)
P - Q = x⁵ - x⁴ + 2x⁴ - 3x³ - 2x³ - 2x² - 4x² + 3x² + x - 2 - 6
P - Q = x⁵ + x⁴ - 5x³ - 3x² + x - 8