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3 years ago

A chief makes one 1 1/2 gallons of soup in a large pot how many one cup servings can the chief get from this large pot of soup

1 answer:

8 0

So,

We need to convert from gal. to c.

16 c. = 1 gal.

$16 * 1 \frac{1}{2} = 16 * \frac{3}{2}$

24 cups

The chef can get 24 cups of soup from his pot.

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7/2x+1/2x = 18+ 9/2x

chubhunter [2.5K]

Answer:

x=-36

Step-by-step explanation:

Add the 7/2x +1/2x to be 8/2x which means that it'll be 4x=18=9/2

then subtract 9/2x on both sides so itll be

$4x=18+\frac{9}{2} x$

-9/2x -9/2x

$-\frac{1}{2} x=18$ because if you do 8/2-9/2 it's -1/2

then multiply the reciprocal to both sides so

$(\frac{2}{-1})(-\frac{1}{2}x)=(\frac{2}{-1})(18)$

which then cancels out -1/2 and makes it

x=-36

4 0

2 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

2 years ago

Lily has 15 shells in her shell collection. Krystal has twice as many shells in her collection as lily does. Mara has 11 fewer s

tester [92]

Mara has 19 shells. I hoped this helped! Mark as branliest if possible!

6 0

2 years ago

Read 2 more answers

A bag of sand originally weighing 144 lb is lifted at a constant rate. As it rises, sand also leaks out at a constant rate. At t

frosja888 [35]

Answer:

Step-by-step explanation:

The bag of sand wave is

W=144lb at x=0

The bag of sand is lifted at a constant rate, i.e the it is not accelerating, so a=0m/s²

Let W be the mass of the sand,

Sand leaks out at a constant rate

dW/dx= C

At a height=18ft, half of the original mass.

i.e x=18ft, M=72lb

We are asked to find the work at 18ft

Work is given as

Work=∫F•dx,

Where F is the force and also the weight of the sand, F=W

The Weight of the bag is a linear function,

dW/dx= C

Then, using variable separation

dW=Cdx

Integrating both sides

∫dW=∫Cdt

W=Cx + B

So, at x=0, W=144

144=B

B=144

W=Cx+144

Also at x=18, W=72lb

72=C×18+144

72-144=18C

-72=18C

C=-4

Then, the weight function becomes

W=-4x+144

W=144-4x

Then applying work formula

Work=∫W•dx

Work=∫(144-4x)dx. x=0 to x=18

Work = 144x-4x²/2. x=0 to x=18

Work=144x-2x² x=0 to x=18

Work=144(18)-2(18²) -0 -0

Work =2592-648

Work =1944 ft lbs

The work done in lifting the sand to 18ft is 1944 ft lbs

7 0

2 years ago

How do you know that substitution give a you the answer to a system of equations

Gwar [14]

Solve each system by substitution. Check your solution. Writing How do you know that substitution gives the answer to a system of equations? ... You Would solve the second equationfor y and then substitute back into the first equation.

6 0

2 years ago