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2 years ago

One liter equals the volume of a 10 cubic centimeters. True False

Chemistry

2 answers:

shtirl [24]2 years ago

6 0

False because it equals 0.01ml

patriot [66]2 years ago

4 0

Yes it does equal 10 cubic centimeters

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Heat energy is always released during what type of process?

Alinara [238K]

In the exothermic process.. Have a great day!

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2 years ago

If you have a 1.0 L buffer containing 0.208 M NaHSO3 and 0.134 M Na2SO3, what is the pH of the solution after addition of 50.0 m

Vlada [557]

Answer:

pH = 7.233

Explanation:

Initially, the buffer contains 0.208 moles of NaHSO₃ and 0.134 moles of Na₂SO₃.

NaHSO₃ reacts with NaOH thus:

NaHSO₃ + NaOH → Na₂SO₃ + H₂O

50.0 mL of 1.00 M NaOH are:

0.0500L × (1mol / 1L) = 0.0500moles of NaOH added. That means after the addition are produced 0.0500moles of Na₂SO₃ and consumed 0.0500moles of NaHSO₃. That means final moles of the buffer are:

NaHSO₃: 0.208 mol - 0.050 mol = 0.158 mol

Na₂SO₃: 0.134 mol + 0.050 mol = 0.184 mol

As pKa of this buffer is 7.167, it is possible to use H-H equation to find pH, thus:

pH = pKa + log₁₀ [Na₂SO₃] / [NaHSO₃]

pH = 7.167 + log₁₀ [0.184] / [0.158]

pH = 7.233

6 0

2 years ago

Cellular respiration occurs? (2 points)

Nataly_w [17]

Answer:

in plant and animal cells

Explanation:

It happens in both and occurs in the mitochondria.

6 0

2 years ago

Read 2 more answers

What general trend do you observe in the electronegativity values of the elements as you go from left to right on the table? Giv

Zanzabum

From left to right the electronegativity increases

8 0

2 years ago

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Enter your answer in the provided box. The usefulness of radiocarbon dating is limited to objects no older than 50,000 yr. What

guapka [62]

Answer : The percent of the carbon−14 left is, 0.242 %

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

To calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{5.73\times 10^3\text{ years}}$

$k=1.205\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount left.

Expression for rate law for first order kinetics is given by :

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant = $1.205\times 10^{-4}\text{ years}^{-1}$

t = time taken for decay process = 50000 years

a = initial amount or moles of the reactant = 7 g

a - x = amount or moles left after decay process = ?

Putting values in above equation, we get:

$1.205\times 10^{-4}=\frac{2.303}{50000\text{ years}}\log\frac{7g}{a-x}$

$a-x=0.0169g$

The amount left of carbon-14 = 0.0169 g

Now we have to calculate the percent of the carbon−14 left.

$\text{Percent of carbon}-14\text{ left}=\frac{\text{Amount left of carbon}-14}{\text{Original amount of carbon}-14}\times 100$

$\text{Percent of carbon}-14\text{ left}=\frac{0.0169g}{7g}\times 100=0.242\%$

Therefore, the percent of the carbon−14 left is, 0.242 %

8 0

2 years ago