We can set up 2 equations given the information.
Let the price of advance ticket be represented by A and same day ticket by S
A + S = 50
20A + 40S = 1700
Solve for A in the first equation by subtracting S on both sides.
U will get A = 50 - S
Now substitute 50 - S for A in the second equation.
20 (50 - S) + 40S = 1700
1000 - 20S + 40S = 1700
20S = 700
S = 35
Same day ticket costs $35 and advance ticket costs $15
9x - 2y = 11 ... (i)
5x - 2y = 15 ... (ii)
Subtracting equation (ii) from (i) we get;
4x + 0 = -4
4x=-4 , x = -1
Replacing x = -1 in equation (i) we get;
9(-1) - 2y = 11
-9 - 2y = 11
-2y = 20
y = 20 ÷ -2 = -10
The solution to the system of equations is (-1,-10).
Answer:
2. The answer should be the last one.
3. The answer should be the first three.
Step-by-step explanation:
<u>Question 2</u>
KE = (1/2)mv²
2KE = mv²
v² = 2KE/m
v = ±√(2KE/m)
Therefore the answer should be the last one.
<u>Question 3</u>
b^(1/2) * b^(5/2)
Remember that the <u><em>product rule</em></u> states that b^x * b^y = b^(x+y)
So this means b^(1/2) * b^(5/2) = b^(1/2+5/2) = b^(6/2) = b^3
Also remember that the <u><em>power rule</em></u> states that √b = b^(1/2)
so this means b^(6/2) can also be written as (√b)^6
Therefore the answer should be the first three.
<em>If you want to double check all of your answers, just replace b with a number (for example, 2), and plug all of the choices into the calculator. Just </em><u><em>make sure</em></u><em> you are </em><u><em>very careful</em></u><em> when typing into the calculator.</em>
Mathrie 134x3= 402 ship names are my specialty:)
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>