<span>You have mentioned that two of the angles of ΔKSD are
∠K=16° and ∠D=34°. So that would mean that ∠S=130°,
because∠K+∠D+∠S=180°. That's because all the angles
of any triangle must total 180°.
But you also say that ∠T=51°. But since no angle of
ΔKSD can equal 51°, neither can any angle of ΔWAT
equal to 51°. Therefore ∠T=51° is impossible!</span>
The answer is 3 8/9 because you turn it into a mixed number which is 5/3*7/3. Once you multiply you get 35/9. Since it is an improper fraction you turn it into a mixed number by dividing 35/9. In the end, you get 3 8/9 as your final answer.
Answer:
4 times
Step-by-step explanation:
Sample space :
6 sided cube = (1, 2, 3, 4, 5, 6)
Coin = (H, T)
Probability = required outcome / Total possible outcomes
Probability of head (H) = P(H) = 1 /2 = 0.5
Probability of 3 = P(3) = 1 /6 = 0.166666
Probability of heads and 3 on a single try = p(H) * p(3) = 0.5 * 0.166666 = 0.083333
Hence, expected number of times this is likely to occur in 48 tries :
0.083333 * 48 = 4
