Question

X2 + y2 - 14x + 10y + 65 = 0 will lie ENTIRELY in Quadrant

Answer 1

Rearranging to standard form 
= (x - 7)^2 + (y + 5)^2 = -65 + 49 + 25
 (x-7)^2 + (y+5)^2 = 9 
so the centre is at (7,-5) and the radius is 3

so the circle will be entirely in Quadrant 4.