Fifteen and sixty two thousanths
Answer:
12 and 14
Step-by-step explanation:
Let the even integers be x and x+2
three times the larger number is expressed as 3(x+2)
30 more than the smaller one is x + 30
Equating both expressions
3(x+2) = x +30
Find x
3x+6 = x+30
3x-x = 30-6
2x = 24
x = 12
The second integer is 12+2 = 14
Hence the required integers are 12 and 14
The range of the given relation is D. R = {-1, 3, 5, 8}.
Step-by-step explanation:
Step 1:
The range of a relation is the second set of values while the domain constitutes the first set of values.
There are 4 given relations with two sets of values so there would be 4 domain values and 4 range values.
Step 2:
The range of (1, -1) = -1,
The range of (2, 3) = 3,
The range of (3, 5) = 5,
The range of (4, 8) = 8.
Combining these values we get the range as {-1, 3, 5, 8} which is option D.