What is the primary visible color of an emission nebula?

1 answer:

7 0

In emission nebulae, there are interstellar clouds of hydrogen, which glow red because of the intense radiation of hot stars inside the nebula

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A vertical cylindrical tank 10 ft in diameter, has an inflow line of 0.3 ft inside diameter and an outflow line of 0.4 ft inside

neonofarm [45]

Answer:

$\frac{dh}{dt} = 1.3 \times 10^{-3} \frac{ft}{s}$ , level is rising.

Explanation:

Since liquid water is a incompresible fluid, density can be eliminated of the equation of Mass Conservation, which is simplified as follows:

$\dot V_{in} - \dot V_{out} = \frac{dV_{tank}}{dt}$

$\frac{\pi}{4}\cdot D_{in}^2 \cdot v_{in}-\frac{\pi}{4}\cdot D_{out}^2 \cdot v_{out}= \frac{\pi}{4}\cdot D_{tank}^{2} \cdot \frac{dh}{dt} \\D_{in}^2 \cdot v_{in} - D_{out}^2 \cdot v_{out} = D_{tank}^{2} \cdot \frac{dh}{dt} \\\frac{dh}{dt} = \frac{D_{in}^2 \cdot v_{in} - D_{out}^2 \cdot v_{out}}{D_{tank}^{2}}$

By replacing all known variables:

$\frac{dh}{dt} = \frac{(0.3 ft)^{2}\cdot (5 \frac{ft}{s} ) - (0.4 ft)^{2} \cdot (2 \frac{ft}{s} )}{(10 ft)^{2}}\\\frac{dh}{dt} = 1.3 \times 10^{-3} \frac{ft}{s}$

The positive sign of the rate of change of the tank level indicates a rising behaviour.

6 0

3 years ago

Fjcivudjxivjsjcjfjs sufi sucks djviw dubai xocovnw divoe

sleet_krkn [62]

Explanation:

gajqbq haiwjwj jajwbw

thanks for the point

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2 years ago

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A car engine burns fuel and has moving parts. Sometimes, an engine can become too hot and overheat. What can prevent the engine

arsen [322]

there many things you could do, one is try getting a cooling system, another thing is its extramly hot and you may need to tunr off your car to prevent the engine from over heating.

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3 years ago

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What is relation of acceleration of a body to its mass and applied force

irinina [24]

The law states that external forces cause objects to accelerate, and the amount of acceleration is directly proportional to the net force and inversely proportional to the mass of the object.

If you can’t copy and paste it just reword it

3 0

3 years ago

What is the average electric current in a wire, when a charge of 150 C passes in 30 s?

NARA [144]

We know, I = Q / t
Here, Q = 150 C
t = 30 s

Substitute their values,
I = 150 / 30
I = 5 A

In short, Your Answer would be 5 Ampere

Hope this helps!

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2 years ago